(x^3+9x^2+20x+12)/(x+2)

Solution for (x^3+9x^2+20x+12)/(x+2) equation:

D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(x^3+9*x^2+20*x+12)/(x+2) = 0

x^3+9*x^2+20*x+12 = 0

x^3+9*x^2+20*x+12 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12 }

1

x = 1

x^3+9*x^2+20*x+12 = 42

1

-1

x = -1

x^3+9*x^2+20*x+12 = 0

-1

x+1

x^2+8*x+12

x^3+9*x^2+20*x+12

x+1

-x^3-x^2

8*x^2+20*x+12

-8*x^2-8*x

12*x+12

-12*x-12

0

x^2+8*x+12 = 0

DELTA = 8^2-(1*4*12)

DELTA = 16

DELTA > 0

x = (16^(1/2)-8)/(1*2) or x = (-16^(1/2)-8)/(1*2)

x = -2 or x = -6

x in { -6, -2, -1} 

(x+6)*(x+2)*(x+1) = 0

(x+6)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+6 )

x+6 = 0 // - 6

x = -6

x in { -1, -6 }